Nernst Equation Calculator

Calculate electrochemical cell potential under non-standard conditions with the Nernst equation, or solve for E°, reaction quotient Q, electrons n or temperature. Includes ΔG.

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    Nernst Equation formula

    E = E° − RTnF ln Q
    SymbolQuantitySI unitMeaning
    ECell potentialVCell (or half-cell) potential under actual conditions
    E°Standard potentialVStandard potential at 1 M, 1 bar
    TTemperatureKAbsolute temperature
    nElectrons transferred—Number of electrons transferred in the balanced reaction
    QReaction quotient—Reaction quotient (products over reactants, as activities)

    What is Nernst Equation?

    Nernst Equation: The potential of an electrochemical cell depends on the standard potential, the temperature, and the ratio of product to reactant activities. — Walther Nernst, 1889

    The Nernst equation corrects a standard electrode potential for real concentrations and temperature. F = 96 485 C/mol is the Faraday constant. At 25 °C the factor RT/F ≈ 25.69 mV, giving the common form E = E° − (0.05916 V / n) log₁₀ Q.

    It underlies pH electrodes and ion-selective electrodes, battery voltage versus state of charge, and the membrane potentials of nerve cells. For a single ion across a membrane the Nernst potential is E = (RT/zF) ln(Cout/Cin).

    How to use this calculator

    1. Choose the quantity you want to find in the Calculate menu. It is highlighted as the result field.
    2. Enter the known values. Scientific notation such as 1.6e-11 is accepted.
    3. Select a unit for each value. Units are converted to SI automatically.
    4. The answer updates as you type. Open Show calculation steps to see the working, or use Copy result to share a link with your inputs.

    Worked example

    A Daniell cell (Zn | Zn²⁺ ‖ Cu²⁺ | Cu, E° = 1.10 V, n = 2) has [Zn²⁺]/[Cu²⁺] = 0.01 at 25 °C.

    1. RT/nF = 8.314 × 298.15 / (2 × 96 485) = 0.01285 V.
    2. E = 1.10 − 0.01285 × ln(0.01) = 1.10 + 0.0592 = 1.159 V.

    Frequently asked questions

    What happens when E = 0?

    The cell is at equilibrium and Q equals the equilibrium constant K, so E° = (RT/nF) ln K. A "dead" battery has reached this state.

    Should I use concentrations or activities?

    Strictly activities. In dilute solutions, molar concentrations (and partial pressures in bar for gases) are a good approximation.